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प्रश्न
Prove that (1 + Δ)(1 – ∇) = 1
योग
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उत्तर
L.H.S = (1 + Δ)(1 – ∇)
= (E)(E–1)
= E1–1
= E°
= 1
= R.H.S
Hence proved.
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Finite Differences
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