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Prakash Borrowed Rs 10,000 from Rajesh for 2 Years at 6% and 8% P.A. Compound Interest for Successive Years. - Mathematics

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प्रश्न

Prakash borrowed Rs 10,000 from Rajesh for 2 years at 6% and 8% p.a. compound interest for successive years. If Prakash returns Rs 5,600 at the end of the first year, how much does he have to give to Rajesh at the end of the second year to clear the loan?

योग
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उत्तर

P = Rs. 10,000, R = 6 °/o p.a.

Interest for first year 

`= ("Rs"  10000 xx 6 xx 1)/100`

= Rs600

Amount due after 1st year

=Rs. 10,000 +Rs. 600 =Rs 10,600 

Amount paid after 1st year = Rs. 5,600 

Balance amount = Rs. 10,600 - Rs. 5,600 =Rs. 5,000 

Interest for second year when r = 8°/o p.a. 

`= ("Rs"  5000 xx 8 xx 1)/100`

= Rs 400 

Amount due after 2nd year

= Rs. 5,000 + Rs. 400

=Rs 5,400

Prakash has to return Rs 5,400 to Rajesh at the end of second year. 

shaalaa.com
Concept of Compound Interest - Compound Interest as a Repeated Simple Interest Computation with a Growing Principal
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Compound Interest - Exercise 1.2 [पृष्ठ ८]

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 1 Compound Interest
Exercise 1.2 | Q 8 | पृष्ठ ८

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