Question

PR = 26 cm, QR = 24 cm, ∠PAQ = 90°, PA = 6 cm and QA = 8 cm. Find ∠PQR

विकल्प

• 80°

• 85°

• 75°

• 90°

Answer 1

90°

Explanation;

Hint:

PR = 26 cm, QR = 24 cm, ∠PAQ = 90°

In the ∆PQR,

PQ = `sqrt("PR"^2 - "QR"^2)`

= `sqrt(26^2 - 24^2)`

= `sqrt(676 - 576)`

= `sqrt(100)` 

= 10

In the right ∆APQ

PQ² = PA² + AQ²

= 6² + 8²

= 36 + 64

= 100

PQ = `sqrt(100)`

= 10

∆PQR is a right angled triangle at Q.

Since PR² = PQ² + QR²

∠PQR = 90°