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प्रश्न
PQ is a tangent drawn from a point P to a circle with centre O and QOR is a diameter of the circle such that ∠POR = 120°. Find ∠OPQ.
योग
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उत्तर
∠POQ = 180° – 120° = 60°
In ∆OPQ, we know
∠POQ + ∠OQP + ∠OPQ = 180° ...(Sum of the angles of a ∆ is 180°)
60° + 90° + ∠OPQ = 180°
∠OPQ = 180° – 150° = 30°
∠OPQ = 30°
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