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Position vector of the mid-point of line segment AB is 3i^+2j^-3k^. If position vector of the point A is 2i^+3j^-4k^, then position vector of the point B is ______. - Mathematics

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प्रश्न

Position vector of the mid-point of line segment AB is `3hati + 2hatj - 3hatk`. If position vector of the point A is `2hati + 3hatj - 4hatk`, then position vector of the point B is ______.

विकल्प

  • `(5hati)/2 + (5hatj)/2 - (7hatk)/2`

  • `4hati + hatj - 2hatk`

  • `5hati + 5hatj - 7hatk`

  • `hati/2 - hatj/2 + hatk/2`

MCQ
रिक्त स्थान भरें
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उत्तर

Position vector of the mid-point of line segment AB is `3hati + 2hatj - 3hatk`. If position vector of the point A is `2hati + 3hatj - 4hatk`, then position vector of the point B is `underlinebb(4hati + hatj - 2hatk)`.

Explanation:

Let, the position vector of point B is `xhati + yhatj + zhatk`.

Now given mid-point of line segment AB is `3hati + 2hatj - 3hatk` and position vector of point A is `2hati + 3hatj - 4hatk`.

∴ `((x + 2)/2)hati + ((y + 3)/2)hatj + ((z - 4)/2)hatk = 3hati + 2hatj - 3hatk`

∴ `(x + 2)/2` = 3, `(y + 3)/2` = 2, `(z - 4)/2` = – 3

`\implies` x = 4, y = 1, z = – 2

∴ Position vector of point B is `4hati + hatj - 2hatk`.

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Position Vector of a Point Dividing a Line Segment in a Given Ratio
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