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प्रश्न
Plot the following point on the cartesian plane:
(–4, 3)
योग
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उत्तर
Given: Point to plot: (–4, 3)
Step-wise calculation:
- Start at the origin O = (0, 0).
- Move along the x-axis to the abscissa x = –4: from (0, 0) go 4 units left to (–4, 0).
- From (–4, 0) move parallel to the y-axis up 3 units (since y = +3) to reach (–4, 3).
- Mark and label that location P(–4, 3).
The point P(–4, 3) is plotted at the position obtained by 4 units left of the origin and 3 units above the x-axis; it lies in Quadrant II.
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