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प्रश्न
P is a point on x-axis with abscissa −6 and Q is (2, 15). Find the distance between P and Q.
योग
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उत्तर
Point P lies on the x-axis with abscissa −6.
P = (−6, 0)
Point Q = (2, 15)
Step: Use the distance formula
The distance between two points (x1,y1) and (x2,y2) is:
Distance = `sqrt((x_2 − x_1) + (y_2 − y_1)^2)`
x1 = −6, y1 = 0
x2 = 2, y2 = 15
`"Distance" = sqrt((2 − (−6))^2 + (15 − 0)^2)`
= `sqrt((8)^2 + (15)^2)`
= `sqrt(64 + 225)`
= 289
= 17 units
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