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P is a point on x-axis with abscissa −6 and Q is (2, 15). Find the distance between P and Q. - Mathematics

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प्रश्न

P is a point on x-axis with abscissa −6 and Q is (2, 15). Find the distance between P and Q.

योग
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उत्तर

Point P lies on the x-axis with abscissa −6.

P = (−6, 0)

Point Q = (2, 15)

Step: Use the distance formula

The distance between two points (x1,y1) and (x2,y2) is:

Distance = `sqrt((x_2 − x_1) + (y_2 − y_1)^2)`

x1​ = −6, y1​ = 0

x2 = 2, y2 = 15

`"Distance" = sqrt((2 − (−6))^2 + (15 − 0)^2)`

= `sqrt((8)^2 + (15)^2)`

= `sqrt(64 + 225)`

= 289

= 17 units

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अध्याय 21: Coordinate Geometry - EXERCISE 21C [पृष्ठ २६१]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 21 Coordinate Geometry
EXERCISE 21C | Q 6. | पृष्ठ २६१
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