Question

P is a point on side BC of a parallelogram ABCD. If DP produced meets AB produced at point L, prove that: DL : DP = AL : DC.

Answer 1

Since AD || BC, that is, AD || BP, 

By the basic proportionality theorem, we get

`(DL)/(DP) = (AL)/(AB)`

Since ABCD is a parallelogram, AB = DC

So, `(DL)/(DP) = (AL)/(DC)`