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On the basis of dimensions, decide which of the following relations for the displacement of a particle undergoing simple harmonic motion is not correct ______. - Physics

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प्रश्न

On the basis of dimensions, decide which of the following relations for the displacement of a particle undergoing simple harmonic motion is not correct ______.

  1. y = `a sin  (2πt)/T`
  2. y = `a sin vt`
  3. y = `a/T sin (t/a)`
  4. y = `asqrt(2) (sin  (2pit)/T - cos  (2pit)/T)`
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उत्तर

b. y = `a sin vt`

c. y = `a/T sin (t/a)`

Explanation:

The argument of trigonometric functions (sin, cos etc.) should be dimensionless. y is displacement and according to the principle of homogeneity of dimensions LHS and RHS.

`[Y] = [L], [a] = [L]`

`[(2pit)/T] = ([T])/([T]) = [T^0]`

`[vt] = [v][t] = [LT^-1][T] = [L]`

`[a/T] = ([a])/([T]) = ([L])/([T]) = [LT^-1]`

`[t/a] = [L^-1T]`

[LHS] ≠ [RHS]

Hence, (c) is not the correct option.

=> LHS ≠ RHS.

So, option (b) is also not correct.

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अध्याय 2: Units and Measurements - Exercises [पृष्ठ ७]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 2 Units and Measurements
Exercises | Q 2.13 | पृष्ठ ७

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