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प्रश्न
On multiplying \[\frac{dy}{dx}-y=\cos x\] throughout by \[e^{-x}\], which equation is obtained?
विकल्प
\[e^{-x}\frac{dy}{dx}-e^{-x}y=e^{-x}\cos x\]
\[e^{-x}\frac{dy}{dx}-y=\cos x\]
\[e^{-x}\frac{dy}{dx}+e^{-x}y=e^{-x}\cos x\]
\[e^{x}\frac{dy}{dx}-e^{x}y=e^{x}\cos x\]
MCQ
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उत्तर
Every term of the equation is multiplied by the integrating factor \[e^{-x}\]. Thus the sign of the \[y\]-term remains negative.
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