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प्रश्न
On a day in Srinagar, the temperature at 6 p.m. was 1°C but at midnight that day, it dropped to −4°C. By how many degrees Celsius did the temperature fall?
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उत्तर
Initial temperature of Srinagar at 6 p.m. = 1°C
Final temperature of Srinagar at midnight = −4°C
Change in temperature = Final temperature - Initial temperature
= (−4 − 1)°C
= −5°C
So, the temperature has changed by −5°C.
The negative sign indicates that the temperature has fallen.
So, the temperature has fallen by 5°C.
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संबंधित प्रश्न
Indicate the following using '+' or '−' sign: 2 km above sea level
Indicate the following using '+' or '−' sign: A deposit of Rs 200
Find the sum of: −18, + 25 and −37
Divide: 0 by –278
Write (T) for true and (F) for false for the following statement:
15 ÷ (−1) = −15
8 + (−8) = ?
Evaluate: (−36) ÷ 6
Simplify: (−9) × 18 − (−9) × 8
An atom changes to a charged particle called ion if it loses or gains electrons. The charge on an ion is the charge on electrons plus charge on protons. Now, write the missing information in the table given below:
| Name of Ion | Proton Charge | Electron Charge | Ion Charge |
| Hydroxide ion | +9 | – | –1 |
| Sodium ion | +11 | – | +1 |
| Aluminium ion | +13 | –10 | – |
| Oxide ion | +8 | –10 | – |
From given integers in Column I match an integer of Column II so that their product lies between –19 and –6:
| Column I | Column II |
| –5 | 1 |
| 6 | –1 |
| –7 | 3 |
| 8 | –2 |
