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प्रश्न
Name the compound prepared by the following reaction:
\[\ce{C2H5Br + KOH (alcoholic solution) ->}\]
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उत्तर
\[\ce{\underset{bromide}{\underset{Ethyl}{C2H5Br}} + KOH (alcoholic solution) → \underset{Ethene}{C2H4} +KBr +H2O}\]
The organic compound formed is Ethene.
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\[\begin{array}{cc}
\phantom{.....................}\ce{H}\phantom{...}\ce{H}\phantom{....}\ce{O}\phantom{...............}\\
\phantom{...........}| \phantom{....}|\phantom{.} \phantom{..}//\phantom{......}\\
\ce{H-C-C-C}\\
\phantom{.......}| \phantom{....}|\phantom{..}\phantom{..}\text{\\} \phantom{..}\\
\phantom{...............}\ce{H}\phantom{...}\ce{H}\phantom{}\phantom{...}\ce{H}\phantom{.........}\
\end{array}\]
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