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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 6

Multiply: 3abc and − 5a2b2c

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प्रश्न

Multiply:

3abc and − 5a2b2c

योग
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उत्तर

3abc × − 5a2b2c

= 3 × − 5 × a1+2 × b1+2 × c1+1

= − 15a3b3c2

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अध्याय 14: Fundamental Concepts (Including Angles and their Properties) - Exercise 19 (C)

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सेलिना Concise Mathematics [English] Class 6 ICSE
अध्याय 14 Fundamental Concepts (Including Angles and their Properties)
Exercise 19 (C) | Q 8.1
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