Advertisements
Advertisements
प्रश्न
Multiply: `2/3"ab"` by `-1/4 "a"^2"b"`
Advertisements
उत्तर
`2/3"ab"xx-1/4"a"^2"b"=(2/3 xx(-1)/4)("ab"xx"a"^2"b")`
`=-1/6"a"^(1+2)."b"^(1+1)`
`=-1/6"a"^3"b"^2`
APPEARS IN
संबंधित प्रश्न
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
a, 2b, 3c
Obtain the product of a, − a2, a3
Express each of the following product as a monomials and verify the result for x = 1, y = 2: \[\left( - \frac{4}{7} a^2 b \right) \times \left( - \frac{2}{3} b^2 c \right) \times \left( - \frac{7}{6} c^2 a \right)\]
Multiply: −8x and 4 − 2x − x2
Multiply: a2, ab and b2
Solve: ( -3x2 ) × ( -4xy)
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is ______.
Multiply the following:
3x2y2z2, 17xyz
Multiply the following:
7pqr, (p – q + r)
