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प्रश्न
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
a, 2b, 3c
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उत्तर
We know that,
Volume = Length × Breadth × Height
Volume = a × 2b × 3c
= (1 × 2 × 3) (a × b × c)
= 6abc
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संबंधित प्रश्न
Find the product of the following pair of monomial.
4p, 0
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Obtain the product of a, 2b, 3c, 6abc.
Obtain the product of m, − mn, mnp.
Express each of the following product as a monomials and verify the result for x = 1, y = 2: \[\left( \frac{1}{8} x^2 y^4 \right) \times \left( \frac{1}{4} x^4 y^2 \right) \times \left( xy \right) \times 5\]
Multiply: 4a and 6a + 7
Multiply: a2, ab and b2
Multiply: `-3/2"x"^5"y"^3` and `4/9"a"^2"x"3"y"`
Solve: (-12x) × 3y2
Area of a rectangle with length 4ab and breadth 6b2 is ______.
