हिंदी

Match the Following Columns: Colum Column Ii (A) the Radii of the Circular Ends of a Bucket, in the Form of the Frustum of a Cone of

Advertisements
Advertisements

प्रश्न

Match the following columns:

Column I Column II
(a) The radii of the circular ends of
a bucket, in the form of the frustum of a cone of height 30 cm, are 20 cm
and 10 cm respectively. The
capacity of the bucket is ........cm3.
(p) 2418π
(b) The radii of the circular ends
 of a conical bucket of height
15 cm are 20 and 12 cm
respectively. The slant height
of the bucket is ........ cm.
(q) 22000
(c) The radii of the circular ends of
a solid frustum of a cone are 33 cm
and 27 cm and its slant height is
10 cm. The total surface area of
the bucket is .........cm2.
(r) 12
(d) Three solid metallic spheres of
radii 3 cm, 4 cm and 5 cm are
melted to form a single solid
sphere. The diameter of the
resulting sphere is ........ cm.
(s) 17
जोड़ियाँ मिलाइएँ
योग
Advertisements

उत्तर

(a)
Let R and r be the top and base of the bucket and let h be its height.

Then, R = 20 cm, r = 10 cm and h = 30 cm.

Capacity of the bucket = Volume of the frustum of the cone

`= (pi"h")/3("R"^2 + "r"^2 + "Rr")`

`= 22/7xx1/3xx30xx[(20)^2 + (10^2) + (20xx10)] "cm"^3`

`= 22/7xx[400+100+200]"cm"^3`

`=(220/7xx700)"cm"^3`

= 22000 cm

Hence, (a) ⇒ (q)

(b)

Let R and r be the top and base of the bucket and let h be its height.

Then, R = 20 cm, r = 12 cm and h = 15 cm

`"Slant height of the bucket"  "l" = sqrt(h^2 + ("R"-r)^2) `

`=sqrt((15)^2 + (20-12)^2)`

`=sqrt(225+64)`

`=sqrt(289) `

= 17 cm

Hence, (b) ⇒ (s)

(c)

Let R and r be the top and base of the bucket and let be its slant height.

Then, R = 33 cm, r = 27 cm and h = 10 cm

Total surface area of the bucket `= pi ["R"^2 +"r"^2+"l"("R" + r)]`

`= pixx[(33)^2 + (27)^2 + 10xx(33+27)]`

`= pi xx [1089 + 729 + 600]`

`= 2418pi  "cm"^2`

Hence, (c) ⇒ (p)

(d)

Let the diameter of the required sphere be d.

Then, volume of the sphere`=4/3 pi"r"^3`

`= 4/3pi("d"/2)^3`

Therefore,

`4/3pi("d"/2)^3 = 4/3pi(3)^3 + 4/3pi(4)^3 + 4/3pi(5)^3`

`=> 4/3pi"d"^3/8 = 4/3pixx[(3)^3+(4)^3 + (5)^3`

`= "d"^3/8 = 216`

⇒ d3 = 1728

⇒ d3 = 12

⇒ d = 12 cm

Hence, (d) ⇒ (r)

Column I Column II
(a) The radii of the circular ends of
a bucket, in the form of the frustum of a cone of height 30 cm, are 20 cm
and 10 cm respectively. The
capacity of the bucket is ........cm3.

(q) 22000

(b) The radii of the circular ends
 of a conical bucket of height
15 cm are 20 and 12 cm
respectively. The slant height
of the bucket is ........ cm.

((s) 17

(c) The radii of the circular ends of
a solid frustum of a cone are 33 cm
and 27 cm and its slant height is
10 cm. The total surface area of
the bucket is .........cm2.

(p) 2418π

(d) Three solid metallic spheres of
radii 3 cm, 4 cm and 5 cm are
melted to form a single solid
sphere. The diameter of the
resulting sphere is ........ cm.

(r) 12

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 17: Volumes and Surface Areas of Solids - Multiple Choice Questions [पृष्ठ ९२५]

APPEARS IN

आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 17 Volumes and Surface Areas of Solids
Multiple Choice Questions | Q 75 | पृष्ठ ९२५
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×