Advertisements
Advertisements
प्रश्न
Making use of the cube root table, find the cube root
7000
Advertisements
उत्तर
We have: \[7000 = 70 \times 100\]
∴ \[\sqrt[3]{7000} = \sqrt[3]{7 \times 1000} = \sqrt[3]{7} \times \sqrt[3]{1000}\]
By the cube root table, we have:
\[\sqrt[3]{7} = 1 . 913 \text{ and } \sqrt[3]{1000} = 10\]
∴ \[\sqrt[3]{7000} = \sqrt[3]{7} \times \sqrt[3]{1000} = 1 . 913 \times 10 = 19 . 13\]
APPEARS IN
संबंधित प्रश्न
Find the smallest number by which the following number must be multiplied to obtain a perfect cube.
72
Find the smallest number by which the following number must be divided to obtain a perfect cube.
81
Find the cubes of the number 7 .
Write the cubes of 5 natural numbers of the form 3n + 2 (i.e. 5, 8, 11, ...) and verify the following:
'The cube of a natural number of the form 3n + 2 is a natural number of the same form i.e. when it is dividend by 3 the remainder is 2'.
What happens to the cube of a number if the number is multiplied by 5?
For of the non-perfect cubes in Q. No. 20 find the smallest number by which it must be multiplied so that the product is a perfect cube.
Find the cube root of the following integer −5832 .
Find the cube-root of 3375.
Find the cube-root of 9.261
The cube root of 250047 is 63
