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प्रश्न
Line ℓ touches a circle with centre O at point P. If radius of the circle is 9 cm, answer the following.

- What is d(O, P) = ? Why ?
- If d(O, Q) = 8 cm, where does the point Q lie?
- If d(PQ) = 15 cm, How many locations of point R are line on line ℓ? At what distance will each of them be from point P?
योग
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उत्तर

i. seg OP is the radius of the circle.
∴ d(O, P) = 9 cm.
ii. Here, 8 cm < 9 cm
∴ d(O, Q) < d(O, P)
∴ d(O, Q) < radius
∴ Point Q lies in the interior of the circle.
iii. There can be two locations of point R on line `l`.
d(O, R) = 15 cm
Now, in ∆OPR, ∠OPR = 90° ...[Tangent theorem]
∴ OR2 = OP2 + PR2 ...[Pythagoras theorem]
∴ 152 = 92 + PR2
∴ 225 = 81 + PR2
∴ PR2 = 225 – 81
= 144
∴ PR = `sqrt(144)`
= 12 cm
∴ Each location of point R will be at a distance of 12 cm from point P. ...[Taking square root of both sides]
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