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प्रश्न
Let \[I=\int e^x\sin x\,dx.\] After applying integration by parts once, which equation is obtained?
विकल्प
\[I=e^x\cos x-\int e^x\cos x\,dx\]
\[I=-e^x\cos x+\int e^x\cos x\,dx\]
\[I=-e^x\sin x-\int e^x\cos x\,dx\]
\[I=e^x\sin x+\int e^x\cos x\,dx\]
MCQ
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उत्तर
Choose \(u=e^x\) and integrate \(\sin x\) to obtain \(-\cos x\). Therefore \(I=-e^x\cos x+\int e^x\cos x\,dx\).
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