Question

Let `A = [(2,1),(0,-2)], B = [(4,1),(-3,-2)] and C = [(-3,2),(-1,4)]`.  Find `A^2 + AC - 5B`

Answer 1

Given,

`A = [(2,1),(0,-2)], B = [(4,1),(-3,-2)] , C = [(-3,2),(-1,4)]`

Thus

`A^2 = [(2,1),(0,-2)][(2,1),(0,-2)] = [(4+0,2-2),(0+0,0+4)] = [(4,0),(0,4)]`

`AC = [(2,1),(0,-2)][(-3,2),(-1,4)] = [(-6-1,4+4),(0+2, 0-8)] = [(-7,8),(2,-8)]`

`5B = 5[(4,1),(-3,-2)] = [(20, 5),(-15,-10)]`

`:. A^2 + AC - 5B = [(4,0),(0,4)] + [(-7,8),(2,-8)] - [(20,5),(-15,-10)] = [(-23,3),(17,6)]`