Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x :
`(sin^-1 x)/sqrt(1 - x^2)`
Advertisements
उत्तर
`int (sin^-1 x)/sqrt(1 - x^2) "d"x`
`sin^-1x` = u
`1/sqrt(1 - x^2) "d"x` = du
`int (sin^-1x)/sqrt(1 - x^2) "d"x = int "u" * "du"`
= `"u"^2/2 + "c"`
`int (sin^-1x)/sqrt(1 - x^2) "d"x = (sin^-1x)^2/2 + "c"`
APPEARS IN
संबंधित प्रश्न
Evaluate : `int_0^1 "x" . "tan"^-1 "x" "dx"`
Evaluate : `int _0^1 ("x" . ("sin"^-1 "x")^2)/sqrt (1 - "x"^2)` dx
Integrate the following functions with respect to x :
`(sin^2x)/(1 + cosx)`
Integrate the following functions with respect to x :
`(1 + cos 4x)/(cos x - tan x)`
Integrate the following functions with respect to x :
`"e"^(x log "a") "e"^x`
Integrate the following functions with respect to x :
`1/((x - 1)(x + 2)^2`
Integrate the following with respect to x :
`x^2/(1 + x^6)`
Integrate the following with respect to x :
`sqrt(x)/(1 + sqrt(x))`
Integrate the following with respect to x :
`1/(x log x log (log x))`
Integrate the following with respect to x:
9xe3x
Integrate the following with respect to x:
`tan^-1 ((8x)/(1 - 16x^2))`
Integrate the following with respect to x:
`"e"^(-x) cos 2x`
Integrate the following with respect to x:
`"e"^(- 3x) sin 2x`
Integrate the following with respect to x:
`"e"^x (tan x + log sec x)`
Integrate the following with respect to x:
`"e"^x sec x(1 + tan x)`
Integrate the following with respect to x:
`"e"^x ((2 + sin 2x)/(1 + cos 2x))`
Choose the correct alternative:
`int ("e"^x (1 + x))/(cos^2(x"e"^x)) "d"x` is
Choose the correct alternative:
`int tan^-1 sqrt((1 - cos 2x)/(1 + cos 2x)) "d"x` is
Choose the correct alternative:
`int x^2 "e"^(x/2) "d"x` is
