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Integrate the following functions with respect to x : 3+4cosxsin2x

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प्रश्न

Integrate the following functions with respect to x :

`(3 + 4cosx)/(sin^2x)`

योग
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उत्तर

`int (3 + 4cosx)/(sin^2x) "d"x = int(3/(sin^2x) + (4cosx)/(sin^2x)) "d"x`

= `int 3/(sin^2x) "d"x + int (4cosx)/sinx * 1/sinx * "d"x`

= `3 int  "cosec"^2 x  "d"x + 4 int cotx  "cosec"  x * "d"x`

= `3 int "cosec"^2x  "d"x + 4 int  "cosec"  x cotx  "d"x`

= 3 × – cot x + 4 × – cosec x + c

= – 3 cot x – 4 cosec x + c

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अध्याय 11: Integral Calculus - Exercise 11.5 [पृष्ठ २०२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 11 Integral Calculus
Exercise 11.5 | Q 7 | पृष्ठ २०२

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