Advertisements
Advertisements
प्रश्न
In what ratio does the line x - y - 2 = 0 divide the line segment joining the points A (3, 1) and B (8, 9)?
Advertisements
उत्तर
Let the line x - y - 2 = 0 divide the line segment joining the points A (3, 1) and B (8, 9) in the ratio k : 1 at P.
Then, the coordinates of P are
`"p" ((8"k"+3)/("k"+1),(9"k"-1)/("k"+1))`
Since, P lies on the line x - y - 2 = 0 we have:
` ((8"k"+3)/("k"+1)) - ((9"k"-1)/("k"+1)) -2=0`
⇒ 8k + 3 - 9k + 1 - 2k - 2 = 0
⇒ 8k - 9k - 2k + 3 + 1 - 2 = 0
⇒ - 3k + 2 = 0
⇒ - 3k = - 2
`⇒ "k" = 2/3`
So, the required ratio is `2/3:1` which is equal to 2 : 3.
APPEARS IN
संबंधित प्रश्न
If the points A(k + 1, 2k), B(3k, 2k + 3) and C(5k − 1, 5k) are collinear, then find the value of k
If G be the centroid of a triangle ABC, prove that:
AB2 + BC2 + CA2 = 3 (GA2 + GB2 + GC2)
If the points A (a, -11), B (5, b), C (2, 15) and D (1, 1) are the vertices of a parallelogram ABCD, find the values of a and b.
Show that the points A(2,1), B(5,2), C(6,4) and D(3,3) are the angular points of a parallelogram. Is this figure a rectangle?
If the point `P (1/2,y)` lies on the line segment joining the points A(3, -5) and B(-7, 9) then find the ratio in which P divides AB. Also, find the value of y.
ABCD is rectangle formed by the points A(-1, -1), B(-1, 4), C(5, 4) and D(5, -1). If P,Q,R and S be the midpoints of AB, BC, CD and DA respectively, Show that PQRS is a rhombus.
Mark the correct alternative in each of the following:
The point of intersect of the coordinate axes is
If the point \[C \left( - 1, 2 \right)\] divides internally the line segment joining the points A (2, 5) and B( x, y ) in the ratio 3 : 4 , find the value of x2 + y2 .
If the points A(1, –2), B(2, 3) C(a, 2) and D(– 4, –3) form a parallelogram, find the value of a and height of the parallelogram taking AB as base.
Write the coordinates of a point on X-axis which is equidistant from the points (−3, 4) and (2, 5).
Two vertices of a triangle have coordinates (−8, 7) and (9, 4) . If the centroid of the triangle is at the origin, what are the coordinates of the third vertex?
Find the area of triangle with vertices ( a, b+c) , (b, c+a) and (c, a+b).
The distance between the points (a cos 25°, 0) and (0, a cos 65°) is
If A (5, 3), B (11, −5) and P (12, y) are the vertices of a right triangle right angled at P, then y=
The area of the triangle formed by (a, b + c), (b, c + a) and (c, a + b)
The distance of the point (4, 7) from the y-axis is
If A(x, 2), B(−3, −4) and C(7, −5) are collinear, then the value of x is
What are the coordinates of origin?
If the points P(1, 2), Q(0, 0) and R(x, y) are collinear, then find the relation between x and y.
Given points are P(1, 2), Q(0, 0) and R(x, y).
The given points are collinear, so the area of the triangle formed by them is `square`.
∴ `1/2 |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)| = square`
`1/2 |1(square) + 0(square) + x(square)| = square`
`square + square + square` = 0
`square + square` = 0
`square = square`
Hence, the relation between x and y is `square`.
Ryan, from a very young age, was fascinated by the twinkling of stars and the vastness of space. He always dreamt of becoming an astronaut one day. So, he started to sketch his own rocket designs on the graph sheet. One such design is given below :

Based on the above, answer the following questions:
i. Find the mid-point of the segment joining F and G. (1)
ii. a. What is the distance between the points A and C? (2)
OR
b. Find the coordinates of the points which divides the line segment joining the points A and B in the ratio 1 : 3 internally. (2)
iii. What are the coordinates of the point D? (1)
