Advertisements
Advertisements
प्रश्न
In the given figure, T is a point on the side PR of an equilateral triangle PQR. Show that PT < QT
Advertisements
उत्तर
In ΔPQR,
PQ = QR = PR
⇒ ∠P = Q = ∠ = 60°
In ΔPQT,
∠PQT < 60°
∴ ∠PQT < ∠P
∴ PT < QT.
APPEARS IN
संबंधित प्रश्न
Complete the hexagonal and star shaped rangolies (see the given figures) by filling them with as many equilateral triangles of side 1 cm as you can. Count the number of triangles in each case. Which has more triangles?
From the following figure, prove that: AB > CD.
In the following figure, write BC, AC, and CD in ascending order of their lengths.
Name the greatest and the smallest sides in the following triangles:
ΔXYZ, ∠X = 76°, ∠Y = 84°.
Arrange the sides of the following triangles in an ascending order:
ΔABC, ∠A = 45°, ∠B = 65°.
ΔABC is isosceles with AB = AC. If BC is extended to D, then prove that AD > AB.
In ΔPQR, PR > PQ and T is a point on PR such that PT = PQ. Prove that QR > TR.
In the given figure, ∠QPR = 50° and ∠PQR = 60°. Show that: SN < SR
ΔABC in a isosceles triangle with AB = AC. D is a point on BC produced. ED intersects AB at E and AC at F. Prove that AF > AE.
In ΔABC, AE is the bisector of ∠BAC. D is a point on AC such that AB = AD. Prove that BE = DE and ∠ABD > ∠C.
