Advertisements
Advertisements
प्रश्न
In the given figure, T is a point on the side PR of an equilateral triangle PQR. Show that PT < QT
Advertisements
उत्तर
In ΔPQR,
PQ = QR = PR
⇒ ∠P = Q = ∠ = 60°
In ΔPQT,
∠PQT < 60°
∴ ∠PQT < ∠P
∴ PT < QT.
संबंधित प्रश्न
Show that in a right angled triangle, the hypotenuse is the longest side.
In the given figure, PR > PQ and PS bisects ∠QPR. Prove that ∠PSR >∠PSQ.

Show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
ABC is a triangle. Locate a point in the interior of ΔABC which is equidistant from all the vertices of ΔABC.
If two sides of a triangle are 8 cm and 13 cm, then the length of the third side is between a cm and b cm. Find the values of a and b such that a is less than b.
Arrange the sides of ∆BOC in descending order of their lengths. BO and CO are bisectors of angles ABC and ACB respectively.

D is a point in side BC of triangle ABC. If AD > AC, show that AB > AC.
Prove that the perimeter of a triangle is greater than the sum of its three medians.
Prove that the hypotenuse is the longest side in a right-angled triangle.
ΔABC in a isosceles triangle with AB = AC. D is a point on BC produced. ED intersects AB at E and AC at F. Prove that AF > AE.
