Question

In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: sin P

Answer 1

ΔQSP is a right-angled triangle.
∴ PQ² = QS² + PS²
= 3² + 4²
= 9 + 16
= 25
⇒ PQ = 5cm
sin P

= `"QS"/"PQ"` 

= `(3)/(5)`.