Question

In the given figure, O is centre of the circle and ∠COD is greater than ∠AOB, then:

विकल्प

• AB > CD

• AB < CD

• AB = CD

• AB + CD = AD

Answer 1

AB < CD

Explanation:

In a circle, equal radii subtend chords such that a larger central angle corresponds to a longer chord. Since it is given that ∠COD is greater than ∠AOB, the chord subtended by ∠COD must be longer than the chord subtended by ∠AOB. Therefore, chord CD > chord AB, which can also be written as AB < CD.