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प्रश्न
In the given figure, O is centre of the circle, AB // DC and ∠ACD = 32°, ∠DAB is equal to:
विकल्प
122°
148°
90°
none of the above
MCQ
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उत्तर
122°
Explanation:
Join DA.
From figure,
In △DAC,
∠DAC = 90° (Angle in semicircle is a right angle)
As, alternate angles are equal.
∴ ∠CAB = ∠ACD = 32°
From figure,
∠DAB = ∠DAC + ∠CAB = 90° + 32° = 122°
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