Advertisements
Advertisements
प्रश्न
In the given figure, BAC is a straight line.
Find:
(i) x
(ii) ∠AOB
(iii) ∠BOC
Advertisements
उत्तर
∵ ∠AOB and ∠COB are linear pairs
∴ ∠AOB + ∠COB = 180°
⇒ x + 25° + 3x + 15° = 180°
⇒ 4x + 40° = 180°
⇒ 4x = 180°− 40° = 140°
(i) ⇒ x =`(140°)/4=35°`
Hence, x = 35°
(ii) ∠AOB = x + 25° = 35° + 25° = 60°
(iii) ∠BOC = 3x + 15° = 3 × 35° + 15°
= 105° + 15° = 120°
APPEARS IN
संबंधित प्रश्न
In the below fig, POQ is a line. Ray OR is perpendicular to line OS is another ray lying
between rays OP and OR. Prove that ∠ROS = 1 (∠QOS − ∠POS).
Define complementary angles.
The supplement of a right angle is ..............
How many lines can be drawn through three
(a) collinear points?
(b) non-collinear points?
In the following figure, ∠AOB and ∠AOC are adjacent angles? Give the reason for your answer.
In the given figure, AB is perpendicular to BC at B.
Find:
(i) the value of x.
(ii) the complement of angle x.
Write the complement of 90°
Write the complement of 21° 17'
Write the supplement of `1/5` of a right angle
In the given figure, the arrows indicate parallel lines. State which angles are equal. Give a reason.
