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प्रश्न
In the given figure, AE : EC = 2 : 3 and BC = 20 cm then DE is equal to ______.

विकल्प
10 cm
12 cm
8 cm
16 cm
MCQ
रिक्त स्थान भरें
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उत्तर
In the given figure, AE : EC = 2 : 3 and BC = 20 cm then DE is equal to 8 cm.
Explanation:
From figure,
In △ ADE and △ ABC,
⇒ ∠DAE = ∠BAC (Common angle)
⇒ ∠ADE = ∠ABC (Corresponding angles are equal)
∴ △ ADE ~ △ ABC (By A.A. postulate)
Given,
AE : EC = 2 : 3
Let AE = 2x and EC = 3x
From figure,
AC = AE + EC = 2x + 3x = 5x
We know that,
Corresponding sides of similar triangle are in proportion.
∴ `(DE)/(BC) = (AE)/(AC)`
⇒ `(DE)/(20) = (2x)/(5x)`
⇒ DE = `20 × 2/5`
⇒ DE = `40/5`= 8 cm
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