हिंदी

In the given figure, AE : EC = 2 : 3 and BC = 20 cm then DE is equal to ______

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प्रश्न

In the given figure, AE : EC = 2 : 3 and BC = 20 cm then DE is equal to ______.

The image displays a triangle ABC with an internal segment DE parallel to the base BC, indicated by matching directional arrows. It illustrates the Basic Proportionality Theorem for analyzing segment proportions and triangle similarity.

विकल्प

  • 10 cm

  • 12 cm

  • 8 cm

  • 16 cm

MCQ
रिक्त स्थान भरें
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उत्तर

In the given figure, AE : EC = 2 : 3 and BC = 20 cm then DE is equal to 8 cm. 

Explanation: 

From figure,

In △ ADE and △ ABC,

⇒ ∠DAE = ∠BAC (Common angle)

⇒ ∠ADE = ∠ABC (Corresponding angles are equal)

∴ △ ADE ~ △ ABC (By A.A. postulate)

Given,

AE : EC = 2 : 3

Let AE = 2x and EC = 3x

From figure,

AC = AE + EC = 2x + 3x = 5x

We know that,

Corresponding sides of similar triangle are in proportion.

∴ `(DE)/(BC) = (AE)/(AC)`

⇒ `(DE)/(20) = (2x)/(5x)`

⇒ DE = `20 × 2/5`

⇒ DE = `40/5`= 8 cm

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अध्याय 15: Similarity (With Applications to Maps and Models) - EXERCISE 15 (B) [पृष्ठ २२०]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 15 Similarity (With Applications to Maps and Models)
EXERCISE 15 (B) | Q 1. (d) | पृष्ठ २२०
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