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प्रश्न
In the given figure, AB is a diameter of the circle with centre O. If ∠BOC = 110°, find ∠ADC.
योग
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उत्तर
AB is a diameter, so central angle.
∠AOB = 180°
Point C lies on arc AB, and we are given
∠BOC = 110°
∠AOC = 180° − 110° = 70°
So arc AC measures 70°.
Angle ∠ADC is an inscribed angle subtending arc AC
∴ ∠ADC = `1/2 xx "arc" AC = 1/2 xx` 70° = 35°
∠ADC = 35°
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