Question

In the given figure, AB = BC = CD and ∠ABC = 132° . Calcualte: ∠AED

Answer 1

In the figure, O is the centre of circle, with AB = BC = CD.
Also, ∠ABC = 132°

Similarly, AB = BC = CD

∠AEB = ∠BEC = ∠CED = 24°

∠AED = ∠AEB + ∠BEC + ∠CED

= 24° + 24° + 24°= 72°