Advertisements
Advertisements
प्रश्न
In the fusion reaction \[^{2}_{1}H + ^{2}_{1}H \rightarrow ^{3}_{2}He + n\] which products are formed and how much energy is released?
विकल्प
Helium-3 + neutron, with 26.7 MeV of energy released
Tritium + proton, with 4.03 MeV of energy released
Helium-3 + neutron, with 3.27 MeV of energy released
Helium-4 + neutron, with 0.42 MeV of energy released
MCQ
Advertisements
उत्तर
When two deuterium nuclei (\[^{2}_{1}H\]) fuse, one possible outcome is \[^{3}_{2}He\] (helium-3) plus a neutron, releasing 3.27 MeV. The alternative deuterium-deuterium reaction produces tritium and a proton with 4.03 MeV.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
