Question

In the following triangle, find the value of x

Answer 1

Given: ∠N = (x + 31)°

∠O = (3x – 10)°

∠P = (2x – 3)°

By angle sum property of a triangle we have

∠N + ∠O + ∠P = O

(x + 31)° + (3x – 10)° + (2x – 3)° = 180°

x + 31°+ 3x – 10° + 2x – 3° = 180°

x + 3x + 2x + 31° – 10° – 3° = 180°

6x + 18° = 180°

6x = 180° + 18°

6x = 162°

x = `(162^circ)/6` = 27°

x = 27°