Question

In the following situation, involved make an arithmetic progression? and why?

The taxi fare after each km when the fare is ₹ 15 for the first km and ₹ 8 for each additional km.

Answer 1

It can be observed that

Taxi fare for 1st km = 15

Taxi fare for first 2 km = 15 + 8 = 23

Taxi fare for first 3 km = 23 + 8 = 31

Taxi fare for first 4 km = 31 + 8 = 39

a₂ - a₁ = 23 - 15 = 8

a₃ - a₂ = 31 - 23 = 8

a₄ - a₃ = 39 - 31 = 8

Clearly 15, 23, 31, 39 … forms an A.P. because every term is 8 more than the preceding term.