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प्रश्न
In the following, find the co-ordinates of the point whose abscissa is the solution of first equation and the ordinate is the solution of the second equation:
`x + x/2 = 9/2` and 2y + (y – 3) = 9
योग
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उत्तर
Given: `x + x/2 = 9/2` and 2y + (y – 3) = 9.
Step-wise calculation:
1. Solve for x:
`x + x/2 = 9/2`
Multiply by 2:
2x + x = 9
⇒ 3x = 9
⇒ x = 3
2. Solve for y:
2y + (y – 3) = 9
2y + y – 3 = 9
⇒ 3y – 3 = 9
⇒ 3y = 12
⇒ y = 4
The required point is (3, 4).
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