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In the following figures, perimeter of ΔABC = perimeter of ΔPQR. Find the area of ΔABC. - Mathematics

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प्रश्न

In the following figures, perimeter of ΔABC = perimeter of ΔPQR. Find the area of ΔABC.

योग
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उत्तर

Given, perimeter of ΔABC = perimeter of ΔPQR

Perimeter of APQR = 14 + 6 + 10 = 30 cm  ...[∵ Perimeter of triangle = Sum of all sides]

Now, perimeter of ΔABC = AB + BC + CA

30 = AB + BC + AC

⇒ 30 = AB + 5 + 13

⇒ 30 = AB + 18

⇒ AB = 30 – 18 = 12 cm

∴ Area of ΔABC = `1/2` × Base × Height

= `1/2 xx 5 xx 12`

= 5 × 6

= 30 cm2

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अध्याय 9: Perimeter and Area - Exercise [पृष्ठ २८३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 7
अध्याय 9 Perimeter and Area
Exercise | Q 85. | पृष्ठ २८३

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