Advertisements
Advertisements
प्रश्न
The area of an equilateral triangle is 36`sqrt3` sq. cm. Find its perimeter.
Advertisements
उत्तर
Area of an equilateral triangle is given by
`sqrt3/4 xx ("side" )^2` = A
`sqrt3/4 xx ("side" )^2 = 36sqrt3`
(side)2 = 144
side = 12 cm
Hence
perimeter = 3 x ( its side )
= 3 x 12
= 36 cm
APPEARS IN
संबंधित प्रश्न
AD is altitude of an isosceles triangle ABC in which AB = AC = 30 cm and BC = 36 cm. A point O is marked on AD in such a way that ∠BOC = 90o. Find the area of quadrilateral ABOC.
If the difference between the sides of a right-angled triangle is 3 cm and its area is 54 cm2; find its perimeter.
The sides of a triangular field are in the ratio 5: 3: 4 and its perimeter is 180 m. Find:
- its area.
- the altitude of the triangle corresponding to its largest side.
- the cost of leveling the field at the rate of Rs. 10 per square meter.
Find the area and the perimeter of quadrilateral ABCD, given below; if AB = 8 cm, AD = 10 cm, BD = 12 cm, DC = 13 cm and ∠DBC = 90°.
Two sides of a triangle are 6.4 m and 4.8 m. If the height of the triangle corresponding to 4.8 m side is 6 m;
find :
(i) area of the triangle ;
(ii) height of the triangle corresponding to 6.4 m sides.
The area of an equilateral triangle is `144sqrt3` cm2; find its perimeter.
Find the area of a triangle whose sides are 27 cm, 45 cm and 36 cm.
Find the area of a triangle with a base 12cm and a height equal to the width of a rectangle having area of 96cm2 and a length of 12cm.
Find the perimeter of A scalene triangle with sides 7 m, 8 m, 10 m
Find the perimeter of An equilateral triangle with side 6 cm
