Question

In the following figure, BA is parallel to CD. Find the angles a, b and c:

Answer 1

In the given figure, 

ABC is a triangle and AB || DC and AC is its transversal.

∠BAC = ∠ACD     (Alternate angles) 

⇒ b = 65°

Again AB || DC and BCE is its transversal

∴ ∠ABC = ∠DCE

⇒ C = 70°

But ∠ACB + ∠ACD + ∠DCE = 180    (Straight line angle)

∴ a + 65° + 70° = 180°

⇒ a + 135° = 180°

⇒ a = 180° - 135° = 45°

Hence a = 45°, b = 65° and c = 70°