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In the following figure, AD is the diameter of the circle with centre O. Chords AB, BC and CD are equal. If ∠DEF = 110°, calculate: ∠AEF

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प्रश्न

In the following figure, AD is the diameter of the circle with centre O. Chords AB, BC and CD are equal. If ∠DEF = 110°, calculate: ∠AEF

योग
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उत्तर


Join AE, OB and OC

∵ AOD is the diameter,

∴ ∠AED = 90°   ...[Angle in a semi-circle]

But ∠DEF = 110°  ...[Given]

∴ ∠AEF = ∠DEF – ∠AED

= 110° –  90°

= 20°

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अध्याय 17: Circles - Exercise 17 (B) [पृष्ठ २६५]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 17 Circles
Exercise 17 (B) | Q 2. | पृष्ठ २६५

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