हिंदी

In the adjoining figure, ∠RQS = 90°, ∠QPS = 90°, RS = 25 cm, QR = 20 cm, PQ = 9 cm. Find PS. - Mathematics

Advertisements
Advertisements

प्रश्न

In the adjoining figure, ∠RQS = 90°, ∠QPS = 90°, RS = 25 cm, QR = 20 cm, PQ = 9 cm. Find PS.

योग
Advertisements

उत्तर

Given: In the figure

∠RQS = 90°

∠QPS = 90°

RS = 25 cm

QR = 20 cm

PQ = 9 cm

Step-wise calculation:

1. In right triangle RQS right angle at Q.

By Pythagoras: 

QS2 + QR2 

= RS2 – QS2

= 252 – 202

= 625 – 400

= 225

⇒ QS = 15 cm

2. In right triangle PQS right angle at P.

By Pythagoras: 

PQ2 + PS2

= QS2 – PS2

= QS2 – PQ2

= 152 – 92

= 225 – 81

= 144

⇒ PS = 12 cm

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Pythagoras Theorem - Exercise 10A [पृष्ठ २१०]

APPEARS IN

नूतन Mathematics [English] Class 9 ICSE
अध्याय 10 Pythagoras Theorem
Exercise 10A | Q 12. | पृष्ठ २१०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×