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प्रश्न
In the adjoining figure, DE = 1.5 m, CD = 30 m, find the length of AC.
योग
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उत्तर
Given:
DE = 1.5 m, CD = 30 m.
The slanted line EA makes a 45° angle with the horizontal at E, so slope = tan 45° = 1.
Points: take D = (0, 0), C = (30, 0), E = (0,1.5). AC is the vertical from C up to A.
Step-wise calculation:
1. Because tan 45° = 1, the rise from E to A equals the run from E to A.
2. Run from E to A = xA – xE
= 30 – 0
= 30
3. Rise from E to A = 30.
So, yA = yE + 30
= 1.5 + 30
= 31.5
4. AC is the vertical distance from C (y = 0) to A (y = 31.5), so AC = 31.5 m.
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