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In parallelogram PQRS, ∠P = (9x – 5)° and ∠Q = (4x – 10)°. Find the values of x and ∠R. - Mathematics

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प्रश्न

In parallelogram PQRS, ∠P = (9x – 5)° and ∠Q = (4x – 10)°. Find the values of x and ∠R.

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उत्तर

In parallelogram PQRS, ∠P = (9x – 5)° and ∠Q = (4x – 10)°


We know the measure of a straight angle is 180°

⇒ ∠P + ∠Q = 180°

⇒ 9x – 5 + 4x – 10 = 180°

⇒ 13x = 180° + 15° 

⇒ 13x = 195°

⇒ x = 15°

The opposite sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.

And ∠P = 9x – 5 = 9 × 15 – 5

⇒ 9 × 15 – 5 = 135 – 5 = 130° = ∠R

Hence, this is required.

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अध्याय 12: Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons) - EXERCISE 12A [पृष्ठ १३९]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 12 Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons)
EXERCISE 12A | Q 2. | पृष्ठ १३९
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