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प्रश्न
In the given figure, ABC is an isosceles triangle whose side AC is produced to E. Through C, CD is drawn parallel to BA. The value of x is
विकल्प
52°
76°
156°
104°
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उत्तर
We are given that;
ΔABC , is isosceles
AB = AC
∠B = ∠C
∠C = 52
And AB || CD
We are asked to find angle x
From the figure we have
∠ACB = 52°
Therefore,
∠A = `180° - 2 xx 52° `
= 76°
Since AB || DC , so
∠ACD = ∠BAC
= 76°
Now
x + 76 = 180
= 180 - 76
= 104
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