In Each of the Following, Find the Value of 'A': 4x2 + Ax + 9 = (2x - 3)2

Find the value of 'a': 4x² + ax + 9 = (2x - 3)²

योग

4x² + ax + 9 = (2x - 3)²Comparing coefficients of x terms, we get
ax = -12x
so, a = -12

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Expansion of Formula

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अध्याय 4: Expansions - Exercise 4 (D) [पृष्ठ ६४]

अध्याय 4 Expansions
Exercise 4 (D) | Q 13.2 | पृष्ठ ६४

Expand: `( 2x - 1/x )( 3x + 2/x )`

Expand : `( 3a + 2/b )( 2a - 3/b )`

If a² + b² + c² = 50 and ab + bc + ca = 47, find a + b + c.

If 2( x² + 1 ) = 5x, find :
(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

If 2( x² + 1 ) = 5x, find :
(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

If 2( x² + 1 ) = 5x, find :
(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

If x² + `x^(1/2)`= 7 and x ≠ 0; find the value of:
7x³ + 8x − `7/x^3 - 8/x`

The difference between two positive numbers is 4 and the difference between their cubes is 316.
Find : Their product

If `(x^2 + 1)/x = 3 1/3` and x > 1; find If `x^3 - 1/x^3`

Find the value of 'a': 4x² + ax + 9 = (2x + 3)²