Advertisements
Advertisements
प्रश्न
In each of the following determine the; value of k for which the given value is a solution of the equation:
x2 + 2ax - k = 0; x = - a.
Advertisements
उत्तर
Since, x = -a is a root of the equation
x2 + 2ax - k = 0
⇒ (-a)2 + 2a x (-a) - k = 0
⇒ a2 - 2a2 - k = 0
⇒ -k = a2
⇒ k = -a2.
संबंधित प्रश्न
Find the values of k for which the given quadratic equation has real and distinct roots:
kx2 + 2x + 1 = 0
Solve the following quadratic equation using formula method only
`2x^2 - 2 . sqrt 6x + 3 = 0`
Find the value of k for which the given equation has real roots:
kx2 - 6x - 2 = 0
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 - 5x + 7 = 0
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 + 5x + 15 = 0.
Determine whether the given quadratic equations have equal roots and if so, find the roots:
x2 + 2x + 4 = 0
If `sqrt(2)` is a root of the equation `"k"x^2 + sqrt(2x) - 4` = 0, find the value of k.
If the one root of the equation 4x2 – 2x + p – 4 = 0 be the reciprocal of the other. The value of p is:
Values of k for which the quadratic equation 2x2 – kx + k = 0 has equal roots is ______.
Find the value of 𝑚 so that the quadratic equation 𝑚𝑥(5𝑥 − 6) = 0 has two equal roots.
