Advertisements
Advertisements
प्रश्न
In each of the following determine the; value of k for which the given value is a solution of the equation:
x2 + 2ax - k = 0; x = - a.
Advertisements
उत्तर
Since, x = -a is a root of the equation
x2 + 2ax - k = 0
⇒ (-a)2 + 2a x (-a) - k = 0
⇒ a2 - 2a2 - k = 0
⇒ -k = a2
⇒ k = -a2.
संबंधित प्रश्न
Find the value of the discriminant in the following quadratic equation:
2x2 - 3x + 1 = O
Solve the following quadratic equation using formula method only
25x2 + 30x + 7 = 0
Find, using the quadratic formula, the roots of the following quadratic equations, if they exist
3x2 – 5x + 2 = 0
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
`2sqrt(3)x^2 - 2sqrt(2)x - sqrt(3) = 0`
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
9a2b2x2 - 48abc + 64c2d2 = 0, a ≠ 0, b ≠ 0
Find the value(s) of m for which each of the following quadratic equation has real and equal roots: x2 + 2(m – 1) x + (m + 5) = 0
Discuss the nature of the roots of the following equation: `5x^2 - 6sqrt(5)x + 9` = 0
If (1 – p) is a root of the equation x2 + px + 1 – p = 0, then roots are:
Assertion (A): If one root of the quadratic equation 4x2 – 10x + (k – 4) = 0 is reciprocal of the other, then value of k is 8.
Reason (R): Roots of the quadratic equation x2 – x + 1 = 0 are real.
If one root of equation (p – 3) x2 + x + p = 0 is 2, the value of p is ______.
