Advertisements
Advertisements
प्रश्न
In a circle, the major arc is 3 times the minor arc. The corresponding central angles and the degree measures of two arcs are
विकल्प
90° and 270°
90° and 90°
270° and 90°
60° and 210°
Advertisements
उत्तर
270° and 90°
We are given the major arc is 3 times the minor arc. We are asked to find the corresponding central angle.
See the corresponding figure.
We know that angle formed by the circumference at the centre is 360°.
Since the circumference of the circle is divided into two parts such that the angle formed by major and minor arcs at the centre are 3x and x respectively.
So 3x + x = 360
4x = 360
x = 90
So m \[\stackrel\frown{AB}\] = 90° and m \[\stackrel\frown{AB}\] = 3x = 270°
APPEARS IN
संबंधित प्रश्न
If O is the centre of the circle, find the value of x in the following figures.
O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.
In the given figure, O is the centre of the circle, prove that ∠x = ∠y + ∠z.
In the given figure, O is the centre of a circle and PQ is a diameter. If ∠ROS = 40°, find ∠RTS.
In the given figure, two circles intersect at A and B. The centre of the smaller circle is Oand it lies on the circumference of the larger circle. If ∠APB = 70°, find ∠ACB.
In the given figure, A is the centre of the circle. ABCD is a parallelogram and CDE is a straight line. Find ∠BCD : ∠ABE.
In the given figure, AB is a diameter of the circle such that ∠A = 35° and ∠Q = 25°, find ∠PBR.
In the given figure, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =
The chord of a circle is equal to its radius. The angle subtended by this chord at the minor arc of the circle is
A circle has radius `sqrt(2)` cm. It is divided into two segments by a chord of length 2 cm. Prove that the angle subtended by the chord at a point in major segment is 45°.
