Question

In an experiment of a simple pendulum, time for 20 oscillations of the pendulum of a given length is measured and recorded as 40 s, 41 s, 42 s, 39 s, and 38 s. Find the absolute error in each measurement.

Answer 1

The time period of 20 oscillations of a simple pendulum are

T₁ = 40 s

T₂ = 41 s

T₃ = 42 s

T₄ = 39 s

T₅ = 38 s

Mean time period of pendulum=`(40+41+42+39+38)/5=40 "s"`

Absolute error ΔT₁ = 40 - 40 = 0

Absolute error ΔT₂ = 40 - 41 = -1

Absolute error ΔT₁ = 40 - 42 = - 2

Absolute error ΔT₃ = 40 - 39 = 1

Absolute error ΔT₁ = 40 - 38 = 2