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In ΔABC, ∠B = 90°, AP = 5, PB = 15, PQ = 17 and QC = 7. Find the values of x and y. - Mathematics

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प्रश्न

In ΔABC, ∠B = 90°, AP = 5, PB = 15, PQ = 17 and QC = 7. Find the values of x and y.

योग
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उत्तर

Given,

ΔABC, ∠B = 90°, AP = 5, PB = 15, PQ = 17 and QC = 7.


Pythagoras theorem states that in a right-angled triangle, the square on the hypotenuse is equal to the sum of the squares on the remaining two sides.

In ΔPBQ,

⇒ PQ2 = PB2 + BQ2

⇒ 172 = 152 + x2

⇒ 172 – 152 = x2

⇒ x2 = 289 – 225 = 64

⇒ x = `sqrt(64)` = 8 cm

And in ΔABC,

⇒ AC2 = AB2 + BC2

⇒ y2 = 202 + 152

⇒ y2 = 400 + 225 = 625

⇒ y = `sqrt(625)` = 25 cm

Hence, this is required.

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अध्याय 11: Pythagoras Theorem - MISCELLANEOUS EXERCISE [पृष्ठ १२९]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 11 Pythagoras Theorem
MISCELLANEOUS EXERCISE | Q 9. | पृष्ठ १२९
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