Advertisements
Advertisements
प्रश्न
In ΔABC, ∠B = 90° , AB = y units, BC = `(sqrt3)` units, AC = 2 units and angle A = x°, find:
- sin x°
- x°
- tan x°
- use cos x° to find the value of y.
Advertisements
उत्तर
(i) From Δ ABC,
sin x° = `"perpendicular"/"Hypotenus" = (sqrt3)/(2)`
(ii) sin x° = `(sqrt3)/(2)`
sin x° = sin 60°
x° = 60°
(iii) tan x° = tan 60°
tan x° = `(sqrt3)`
(iv) cos x° = `"y"/2`
cos 60° = `"y"/2`
`1/2 = "y"/2`
`2/2` = y
∴ y = 1
APPEARS IN
संबंधित प्रश्न
If sin x + cos y = 1 and x = 30°, find the value of y
Find the magnitude of angle A, if 2 sin A cos A - cos A - 2 sin A + 1 = 0
Find the value of 'A', if 2 cos A = 1
If θ = 30°, verify that: sin 3θ = 4sinθ . sin(60° - θ) sin(60° + θ)
In a rectangle ABCD, AB = 20cm, ∠BAC = 60°, calculate side BC and diagonals AC and BD.
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
Evaluate the following: `(tan42°)/(cot48°) + (cos33°)/(sin57°)`
Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
If cosθ = sin60° and θ is an acute angle find the value of 1- 2 sin2θ
