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प्रश्न
In a rectangular loop in a uniform magnetic field, the sides BC and AD are perpendicular to \[\vec{B}\]. The magnitude of the force on each of these sides is:
विकल्प
\[F_1 = BIl\] and \[F_2 = BIl\]
\[F_1 = 0\] and \[F_2 = 0\]
\[F_1 = BIA\] and \[F_2 = BIA\]
\[F_1 = BIb\] and \[F_2 = BIb\]
MCQ
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उत्तर
The sides BC and AD, each of breadth b, are perpendicular to \[\vec{B}\], so each experiences a force \[F = BIb\]. These two equal and opposite forces form the couple responsible for the torque on the loop.
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